$\text{ABC}$ forms an equilateral triangle in which $\text{B}$ is $2$ km from $\text{A}$. A person starts walking from $\text{B}$ in a direction parallel to $\text{AC}$ and stops when he reaches a point $\text{D}$ directly east of $\text{C}$. He, then, reverses direction and walks till he ... north of $\text{A}$ $3$ km east and $1$ km south of $\text{A}$ $3$ km west and $3$ km north of $\text{A}$
asked
Jan 17, 2016
in Logical Reasoning
makhdoom ghaya
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