edited by
318 views
1 votes
1 votes

Two cars travel from different locations at constant speeds. To meet each other after starting at the same time, they take $1.5$ hours if they travel towards each other, but $10.5$ hours if they travel in the same direction. If the speed of the slower car is $60 \mathrm{~km} / \mathrm{hr}$, then the distance traveled, in $\mathrm{km}$, by the slower car when it meets the other car while traveling towards each other, is

  1. $100$
  2. $90$
  3. $150$
  4. $120$
edited by

Please log in or register to answer this question.

Answer:

Related questions

1 votes
1 votes
1 answer
1
1 votes
1 votes
1 answer
2
admin asked Mar 3, 2023
1,788 views
If $c=\dfrac{16 x}{y}+\dfrac{49 y}{x}$ for some non-zero real numbers $x$ and $y,$ then $c$ cannot take the value$-60$ $-50$ $60$ $-70$
2 votes
2 votes
1 answer
3
admin asked Mar 3, 2023
403 views
If $(3+2 \sqrt{2})$ is a root of the equation $a x^{2}+b x+c-0$, and $(4+2 \sqrt{3})$ is a root of the equation $a y^{2}+m y+n – 0$, where $a, b, c, m$ and $n$ are inte...
1 votes
1 votes
0 answers
4
admin asked Mar 3, 2023
316 views
Suppose the medians $\mathrm{BD}$ and $\mathrm{CE}$ of a triangle $\mathrm{ABC}$ intersect at a point $\mathrm{O}$. If area of triangle $\mathrm{ABC}$ is $108$ $\mathrm{s...