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Let $a, b, c$ be non-zero real numbers such that $b^{2}<4 a c$, and $f(x)=a x^{2}+b x+c$. If the set $S$ consists of all integers $m$ such that $f(m)<0$, then the set $S$ must necessarily be

  1. either the empty set or the set of all integers
  2. the set of all integers
  3. the set of all positive integers
  4. the empty set

1 Answer

1 1 vote

Logic :  if the discriminant is less than 0 then the quad equation cant have any roots
 
which would mean, it can NEVER intersect the X axis.

Now if a > 0  then the graph will be a upward facing parabola as F''(x) = 2a 

So value of a would decide if it is a upward/downward facing parabola

So for a> 0  we will have a upward facing parabola with it not crossing the X axis ever

and for a < 0 we will have a downward facing parabola wih it never crossing the X axis ever

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