0 0 votes A bought an article and spent $\text{Rs. 110}$ on its repair. He then sold it to $\text{B}$ at $20 \%$ profit, $\text{B}$ sold it to $\text{C}$ at a loss of $10 \%$ and $\text{C}$ sold it for $\text{Rs. 1188}$ at a profit of $10 \%$. What is the amount for which $\text{A}$ bought the article? $\text{Rs. 850}$ $\text{Rs. 950}$ $\text{Rs. 930}$ $\text{Rs. 890}$ Quantitative Aptitude nielit2022feb-scientistd + – Lakshman Bhaiya 12.2k points 1.9k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
0 0 votes let x = amount for he bought + amount spent on repair x--->[x+(20%of x)=1.2x]--->[1.2x-(10% of 1.2x)=1.08x]--->[1.08x+(10%of1.08x)] Given in question 1.08x+(10% of 1.08x)=1188 from this x=1000 you get Required answer = 1000 – 110 = 890. Therefore answer is option D Shamshuddin answered Sep 18, 2022 Shamshuddin 34 points comment Share Follow 0 reply Please log in or register to add a comment.