Let’s assume that number is $x$
it is given that $x>44^2=1936$ and $x<45^2=2025$
it is also given that the factor is $6^2=36$ and the number is multiple of 5.
we can find $LCM(36,5)=180$
therefore our number should be multiple of $180$
Only option $(B)$ satisfied the condition.
Option $(B)$ is correct.