Let $\text{C}$ be a circle with centre $\text{P}_0$ and $\text{AB}$ be a diameter of $\text{C}.$ suppose $\text{P}_1$ is the mid-point of the line segment $\text{P}_0\text{B}, \text{P}_2$ is the mid-point of the line segment $\text{P}_1\text{B}$ and so on. Let $\text{C}_1$, $\text{C}_2, \text{C}_3, \dots $ be the circles with diameters $\text{P}_0 \text{P}_1, \text{P}_1 \text{P}_2, \text{P}_2 \text{P}_3 ,\dots $ respectively. Suppose the circles are all shaded. The ratio of the area of the unshaded portion of $\text{C}$ to that of the original circle $\text{C}$ is
- $8:9$
- $9:10$
- $10:11$
- $11:12$