Dick is thrice as old as Tom and Harry is twice as old as Dick. If Dick’s age is $1$ year less than the average age of all three, then Harry’s age, in years, is

Given information:
- Dick is thrice as old as Tom. Let Tom's age be x.
- Harry is twice as old as Dick.
- Dick's age is 1 year less than the average age of all three.

Step 1: Express Dick's age in terms of Tom's age (x).
Dick's age = 3x

Step 2: Express Harry's age in terms of Dick's age.
Harry's age = 2 × Dick's age = 2 × 3x = 6x

Step 3: Set up an equation for Dick's age being 1 year less than the average age of all three.
Dick's age = (Tom's age + Dick's age + Harry's age)/3 - 1
3x = (x + 3x + 6x)/3 - 1
3x = 10x/3 - 1
9x = 10x - 3
x = 3

Step 4: Find Harry's age by substituting x = 3 into the expression for Harry's age.
Harry's age = 6x = 6 × 3 = 18 years

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