0 0 votes A cylindrical box of radius $5$ cm contains $10$ solid spherical balls each of radius $5$ cm. If the topmost ball touches the upper cover of the box, then the volume of the empty space in the box is: $\dfrac{2500\pi}{3}$ cubic cm $500\pi$ cubic cm $2500\pi$ cubic cm $\dfrac{5000\pi}{3}$ cubic cm Quantitative Aptitude nielit2019feb-scientistc quantitative-aptitude geometry + – Lakshman Bhaiya 12.2k points 2.1k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
1 1 vote Ans is option (A) Height of the cylinder $=10\times(2\times5cm)=100cm$ . $\therefore$ Volume of empty space in the box: $\pi r^{2}h-(10\times\frac{4}{3}\times \pi \times r^{3})$ cubic cm. $\Rightarrow$ $(\pi \times 25\times50)-(10\times\frac{4}{3}\times \pi \times 5^{3})=\frac{2500}{3}$ cubic cm. haralk10 answered Apr 21, 2021 haralk10 838 points comment Share Follow 0 reply Please log in or register to add a comment.