1 1 vote A train running at the speed of $60$ km/hr crosses a pole in $9$ seconds. What is the length of the train? $120$ meters $180$ meters $324$ meters $150$ meters Quantitative Aptitude nielit2017july-scientistb speed-distance-time + – Lakshman Bhaiya 12.2k points 2.8k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
1 1 vote Given that, speed of the train $S = 60\;km/hr = 60 \times \dfrac{1000}{60 \times 60}\;m/sec = \dfrac{50}{3}\;m/sec$ and, time to cross the pole $T =9\;sec $ Let’s lenth of the train $ = D\;m$ We know that $S = \dfrac{D}{T}$ $\implies D = S \times T$ $\implies D = \dfrac{50}{3}\;m/sec \times 9\;sec$ $\implies D = 150\;m.$ So, the correct answer is $(D).$ Lakshman Bhaiya answered Aug 7, 2020 Lakshman Bhaiya 12.2k points comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes $\textrm{The speed of train is given in km/hr & length of the train is asking in the meter.}$ $\textrm{To convert the speed of the train to km/hr to m/sec we have to multiply by 5/18.}$ $\because$ $\textrm{1km=1000m & 1hr=3600sec}$ $\therefore$ $\textrm{60km/hr= ($\frac{60*5}{18}$)m/sec}$ $\textrm{Speec Of train}$ $\Rightarrow$ ($\frac{50}{3})m/sec$ $Time=9sec$ $\because$ $\textrm{Speed=$\frac{Distance}{Time}$}$ $\Rightarrow$ $\textrm{Distance=Speed*Time}$ $\therefore$ $\textrm{Distance=($\frac{50}{3}*9$)m/sec}$ $\textrm{Distance=150m}$ $\therefore$ $\textrm{Length of train is150m,Option D.}$ Hira Thakur answered Jun 7, 2020 Hira Thakur 6.9k points comment Share Follow 0 reply Please log in or register to add a comment.