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What is the measure of the radius of the circle that circumscribes a triangle whose sides measure $9, 40$ and $41$?

1. $6$
2. $4$
3. $24.5$
4. $20.5$
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$9^{2}$+$40^{2}$=$41^{2}$
Therefore, the radius of the circle that circumscribes the triangle = $\frac{41}{2}$ = 20.5