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What is the measure of the radius of the circle that circumscribes a triangle whose sides measure $9, 40$ and $41$?

  1. $6$
  2. $4$
  3. $24.5$
  4. $20.5$
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Option D. 20.5

Triangle with sides 9, 40 and 41 is a right triangle.
$9^{2}$+$40^{2}$=$41^{2}$
In a right angled triangle, the radius of the circle that circumscribes the triangle is half the hypotenuse.
Therefore, the radius of the circle that circumscribes the triangle = $\frac{41}{2}$ = 20.5

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