# NIELIT 2017 DEC Scientist B - Section A: 59

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What is the measure of the radius of the circle that circumscribes a triangle whose sides measure $9, 40$ and $41$?

1. $6$
2. $4$
3. $24.5$
4. $20.5$

Option D. 20.5

Triangle with sides 9, 40 and 41 is a right triangle.
$9^{2}$+$40^{2}$=$41^{2}$
In a right angled triangle, the radius of the circle that circumscribes the triangle is half the hypotenuse.
Therefore, the radius of the circle that circumscribes the triangle = $\frac{41}{2}$ = 20.5

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