0
votes

What is the measure of the radius of the circle that circumscribes a triangle whose sides measure $9, 40$ and $41$?

- $6$
- $4$
- $24.5$
- $20.5$

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0
votes

What is the measure of the radius of the circle that circumscribes a triangle whose sides measure $9, 40$ and $41$?

- $6$
- $4$
- $24.5$
- $20.5$

See all

2
votes

**Option D. 20.5**

Triangle with sides 9, 40 and 41 is a right triangle.

$9^{2}$+$40^{2}$=$41^{2}$

In a right angled triangle, the radius of the circle that circumscribes the triangle is half the hypotenuse.

Therefore, the radius of the circle that circumscribes the triangle = $\frac{41}{2}$ = 20.5

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