0 0 votes Find the sum $\sqrt{1+ \frac{1}{1^2} + \frac{1}{2^2} } + \sqrt{1+ \frac{1}{2^2} + \frac{1}{3^2} } + \dots + \sqrt{1+ \frac{1}{2007^2} + \frac{1}{2008^2} }$ $2008 - \frac{1}{2008}$ $2007 - \frac{1}{2007}$ $2007 - \frac{1}{2008}$ $2008 - \frac{1}{2007}$ $2008 - \frac{1}{2009}$ Quantitative Aptitude cat2008 quantitative-aptitude sequences&series + – go_editor 14.2k points 1.6k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
0 0 votes Option A : 2008 - 1/2008 Jouher Sharief answered Feb 24 Jouher Sharief 42 points comment Share Follow 0 reply Please log in or register to add a comment.