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Can someone explain answer for this question(26)?
asked
Dec 5, 2018
in
Quantitative Aptitude
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ranarajesh495
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all options are wrong answer is $\frac{1}{3}$
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Total number of balls = 8 + 7 + 6 = 21
Let E be the event of selecting neither red nor green ball
Then n(E) = 7
Required probability = 7/21 = 1/3
answered
Dec 8, 2018
by
mudit23june
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