Can someone explain answer for this question(26)?
In a box, there are $8$ red, $7$ blue and $6$ green balls. One ball is picked up randomly. What is the probability that it is neither red nor green ?
- $\frac{2}{3}$
- $\frac{3}{4}$
- $\frac{7}{19}$
- $\frac{9}{21}$