$A$ does $\dfrac{1}{2}^{th}$ work in $7$ days

So, in $\dfrac{7}{\dfrac{1}{2}} = 7 \times 2 = 14 $ days $A$ can complete the whole work

$B$ does $\dfrac{1}{3}^{th}$ work in $14$ days

So, in $\dfrac{14}{\dfrac{1}{3}} = 14 \times 3 = 42 $ days $B$ can complete the whole work

Now, remaining work = $\left ( 1 - \dfrac{1}{2} + \dfrac{1}{3} \right ) = \left ( 1 - \dfrac{5}{6} \right ) = \dfrac{6 - 5}{6} = \dfrac{1}{6}$

& $20\%$ of the remaining work = $\dfrac{1}{6} \times 20\% =\dfrac{1}{6} \times \dfrac{1}{5} =\dfrac{1}{30}$

∴ $C$ does $\dfrac{1}{30}^{th}$ work in $\dfrac{28}{5}$ days

So, in $\dfrac{\dfrac{28}{5}}{\dfrac{1}{30}} = \dfrac{28}{5} \times 30 = 28 \times 6 = 168$ days $C$ can complete the whole work

Now, LCM of $(14, 42, 168) = 168$

∴ Total units of work = $168 $ units

∴ $A$ can complete $\dfrac{168}{14} = 12$ units of work in $1$ day

$B$ can complete $\dfrac{168}{42} = 4$ units of work in $1$ day

$C$ can complete $\dfrac{168}{168} = 1$ units of work in $1$ day

When $A, B, C$ works together in $1$ day total work done = $12+4+1 = 17$ units

∴ To complete $168$ units $A, B, C $ have to work for $\dfrac{168}{17} = 9.88$ days

∴ To complete the whole work $A, B, C$ have to work together for $9.88$ days.

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which one