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I'm rotating the reference frame by 45**°** anti-clockwise.

We're splitting UT into vertical and horizontal distance.

**∴ **By 45-45-90 triangle we get UV = UT = 2.8 / √2 = 2.8/1.4 = 2 km.

**∴ **The **vertical distance** between start point and end point is = 8 - 2.8 - 2

= **3.2 km**

And the **horizontal distance** between start point and end point is = 8 - 5 - 2

= **1 km**

Therefore, The distance between starting and ending point will be the hypotenuse of right angle triangle with perpendicular sides 3.2 and 1.

**∴ Required Distance** = √ ( (3.2)^{2} + (1)^{2 })

= √ (10.24 + 1)

= √ (11.24)

= **3.35**