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Four friends start from four towns, which are at the four corners of an imaginary rectangle. They meet at a point which falls inside the rectangle, after travelling distances of4O, 50, and 60 metres. The maximum distance that the fourth could have travelled is (approximately):

  1. 67 metres
  2. 52 metres
  3. 22.5 metres
  4. Cannot be determined
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We need to pair up the distances in a way such that, D's distance is to be maximum.

OC2 + OB2 = OA2 + OD2

   602 + 502 = 402 + OD2

   ( 3600 + 2500) = 1600 + OD2

   (6100 - 1600) = OD2

   OD = √4500

   ∴ OD = 67.08

The ans. will be A. 67 metres .

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