2 2 votes Four friends start from four towns, which are at the four corners of an imaginary rectangle. They meet at a point which falls inside the rectangle, after travelling distances of4O, 50, and 60 metres. The maximum distance that the fourth could have travelled is (approximately): 67 metres 52 metres 22.5 metres Cannot be determined Quantitative Aptitude cat1994 quantitative-aptitude time-and-distance + – Misbah Ghaya 8.6k points 11.1k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
Best answer 2 2 votes We need to pair up the distances in a way such that, D's distance is to be maximum. ∴ OC2 + OB2 = OA2 + OD2 602 + 502 = 402 + OD2 ( 3600 + 2500) = 1600 + OD2 (6100 - 1600) = OD2 OD = √4500 ∴ OD = 67.08 The ans. will be A. 67 metres . Subarna Das answered Dec 26, 2017 • selected Dec 27, 2017 by Sukanya Das Subarna Das 2.4k points comment Share Follow See 1 comment 1 1 comment reply s33dy 10 points commented Jan 9, 2025 reply Follow flag How do you know which side is what, it could also 502 + x2 = 602 + 402 0 0 replyShare Please log in or register to add a comment.