Total investment in $1995 = \left (2981.1 + 7081.6 \right) = 10062.7 \hspace{0.1cm}Rs.$
Whereas, Total investment in $1996 = \left (3489.5 + 8352.0 \right) = 11841.5 \hspace{0.1cm}Rs. $
∴ Total investment of $1996$ is $\left [\dfrac{(11841.5-10062.7)}{10062.7} = 0.1767 \hspace{0.1cm} \right ] i.e. \hspace{0.1cm} 17.67\%$ greater than the total investment of $1995$.
∴ The answer will be Option D )