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CMI2010-A-07

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Let X=$\frac{n(5n+1)(10n+1)}{6}$

For n=1  X= $\frac{6*11}{6}=11$

For n=2  X=$\frac{2*11*21}{6}=77$

For n=3  X=$\frac{3*16*31}{6}=248$

For n=4  X=$\frac{4*21*41}{6}=574$

Here we can see X is not divisible 3 and 5 but  X is always an Integer.

 

Hence,Option(C)Is always an integer.

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