0 0 votes Let $n (>1)$ be a composite integer such that $\sqrt{n}$ is not an integer. Consider the following statements $n$ has a perfect integer–valued divisor which is greater than $1$ and less than $\sqrt{n}$. $n$ has a perfect integer–valued divisor which is greater than $\sqrt{n}$ but less than $n.$ Then, Both A and B are false A is true but B is false A is false but B is true Both A and B are true Quantitative Aptitude cat2003-2 quantitative-aptitude number-systems + – go_editor 14.2k points 1.1k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.