Based on the figure below, what is the value of $x,$ if $y = 10?$
We can find the value of $x$ by checking with the given options.
Consider $\triangle ADE$ using Pythagoras Theorem and put $x=11$
$y^2=(x-3)^2+(DE)^2$, put $y=10$ and after solving we get $DE=6$.
now consider $\triangle BCD$ using Pythagoras theorem $(BD)^2=(BC)^2+(DC)^2$
$\implies 289=289$ which satisfies the condition.
Option (B) is correct.