0 0 votes Suppose $x_{1}, x_{2}, x_{3}, \ldots, x_{100}$ are in arithmetic progression such that $x_{5}=-4$ and $2 x_{6}+2 x_{9}=x_{11}+x_{13}$. Then, $x_{100}$ equals$206$$204$$-194$$-196$ Others cat2024-set1 + – Shubham Sharma 2 3.9k points 381 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.