edited by
340 views
0 votes
0 votes

The internal bisector of an angle $\text{A}$ in a triangle $\text{ABC}$ meets the side $\text{BC}$ at point $\text{D. AB = 4, AC = 3}$ and angle $\text{A} = 60^{\circ}$. Then what is the length of the bisector $\text{AD}?$

  1. $\frac{12 \sqrt{3}}{7}$
  2. $\frac{12 \sqrt{13}}{7}$
  3. $\frac{4 \sqrt{13}}{7}$
  4. $\frac{4 \sqrt{3}}{7}$
edited by

Please log in or register to answer this question.

Related questions

769
views
0 answers
0 votes
go_editor asked May 2, 2016
769 views
Answer the question based on the diagramIn the diagram below Angle $\text{ABC} = 90^{\circ} = \text{Angle DCH = Angle DOE = Angle EHK = Angle FKL = Angle GLM = Angle LMN...
738
views
0 answers
0 votes
go_editor asked Mar 2, 2016
738 views
Answer the question based on the diagramIn the diagram below Angle $\text{ABC} = 90^{\circ} = \text{Angle DCH = Angle DOE = Angle EHK = Angle FKL = Angle GLM = Angle LMN...
326
views
0 answers
0 votes
go_editor asked Mar 2, 2016
326 views
The area of the triangle with the vertices $(a,a), (a+1, a)$ and $(a, a+2)$ is$a^3$$1$$0$None of these
256
views
0 answers
0 votes
go_editor asked Mar 2, 2016
256 views
There is a common chord of $2$ circles with radius $15$ and $20.$ The distance between the two centres is $25.$ The length of the chord is$48$$24$$36$$28$
346
views
0 answers
0 votes
go_editor asked Mar 2, 2016
346 views
In the figure given below, find the distance $\text{PQ}.$ $7$ m$4.5$ m$10.5$ m$6$ m