$(BE)^{2} = MPB$, where $B, E, M$ & $P$ are distinct integers, then $M$?

There is only one possibility.

$19^{2}=361$

Here B=1

E=9

M=3

P=6

Here all numbers are distinct.

Hence,Option(B) 3 should be the correct choice.

196 Points

152 Points

94 Points

66 Points

46 Points

Aptitude Overflow