1 votes 1 votes Let M be the set of all even numbers from 1 to 25 and all the odd numbers between 26 and 200. If all the elements of M are multiplied, find the number of zeroes at the end of this product.22182321 Quantitative Aptitude quantitative-aptitude + – makhdoom ghaya asked Aug 22, 2015 makhdoom ghaya 8.1k points 2.8k views answer comment Share See all 0 reply Please log in or register to add a comment.
0 votes 0 votes We get a 0, when we multiply 2 and 5 together. For even numbers from 1 to 25, we get 12 + 6 + 3 = 21 2's. For odd numbers from 26-200 we get 25 + 5 + 1 = 31 5's. So, their multiple will have min(21, 31) = 21 zeroes at end. Arjun answered Sep 2, 2015 Arjun 8.6k points comment Share See 1 comment See all 1 1 comment reply Shubham Saxena 1 12 points commented Jan 6, 2018 reply Share Sir, we can get zero by two cases. I. When we multiply 2 by 5 and II. When already there is zero at the end.(like in 10) So taking forward your solution, we get 21 zero's from I case and two more zero's from II case i.e. from 10 and 20. Final answer would be =21+2=23. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes 4.21 Ginna answered Apr 24, 2022 Ginna 402 points comment Share See all 0 reply Please log in or register to add a comment.