Aptitude Overflow - Recent questions and answers in Quantitative Aptitude
https://aptitude.gateoverflow.in/qa/quantitative-aptitude
Powered by Question2AnswerAnswered: work and time
https://aptitude.gateoverflow.in/4857/work-and-time?show=4877#a4877
<p><img alt="" src="https://aptitude.gateoverflow.in/?qa=blob&qa_blobid=3030005972429334680"></p>
<p>Answer : 4 days </p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/4857/work-and-time?show=4877#a4877Fri, 17 May 2019 13:57:33 +0000Answered: work and wages(self doubts)
https://aptitude.gateoverflow.in/4859/work-and-wages-self-doubts?show=4876#a4876
1/A = 1/B + 1/C (i)<br />
<br />
1/A + 1/B = 1/10 (ii)<br />
<br />
It is given that C can alone do the work in 50 days. So, (i) becomes<br />
<br />
1/A – 1/B = 1/50 (iii)<br />
<br />
Solving (ii) & (iii), we get B = 25 daysQuantitative Aptitudehttps://aptitude.gateoverflow.in/4859/work-and-wages-self-doubts?show=4876#a4876Mon, 13 May 2019 05:52:33 +0000Answered: work and time (self doubts)
https://aptitude.gateoverflow.in/4858/work-and-time-self-doubts?show=4863#a4863
Work done by $A$ in $1$ hour =$\frac{1}{4}$<br />
<br />
Work done by $B$ and $C$ in $1$ hour=$\frac{1}{3}$<br />
<br />
Work done by $A$ and $C$ in $1$ hour=$\frac{1}{2}$<br />
<br />
<br />
Work done by $A$ ,$B$ and $C$ in $1$ hour=$\frac{1}{4} +\frac{1}{3}=\frac{7}{12}$<br />
<br />
Work done by $B$ in $1$ hour $=$ (Work done by $A$ ,$B$ and $C$ in $1$ hour)$-$(Work done by $A$ and $C$ in $1$ hour)<br />
<br />
$=$$\frac{7}{12} - \frac{1}{2} = \frac{1}{12}$<br />
<br />
<br />
$B$ alone will take time to complete his work =12 HoursQuantitative Aptitudehttps://aptitude.gateoverflow.in/4858/work-and-time-self-doubts?show=4863#a4863Tue, 30 Apr 2019 05:41:59 +0000Answered: triangle
https://aptitude.gateoverflow.in/4860/triangle?show=4861#a4861
a(base)+b(height)+c(hypotenus)=60<br />
<br />
a+b+26=60<br />
a2+b2=26*26 eq. . 1<br />
a+b=34<br />
<br />
a2+b2+2ab=34*34<br />
<br />
26*26+2ab=34*34<br />
<br />
a*b=240<br />
<br />
Area of right angle triangle=1/2base*height<br />
<br />
=1/2(a*b)<br />
=1/2(240)<br />
120Quantitative Aptitudehttps://aptitude.gateoverflow.in/4860/triangle?show=4861#a4861Thu, 25 Apr 2019 06:54:09 +0000work and wages
https://aptitude.gateoverflow.in/4856/work-and-wages
A and B took a job to be completed in 20 days. They started working together and after 12 days, C joined them and the whole job finished in 15 days. How much time would C require to complete the job if only C was hired?Quantitative Aptitudehttps://aptitude.gateoverflow.in/4856/work-and-wagesTue, 16 Apr 2019 04:34:41 +0000self doubts
https://aptitude.gateoverflow.in/4855/self-doubts
Two friends A and B were employed to do a work. Initial deadline was fixed at 24 days. Both started working together but after 20 days, A left the work and the whole work took 30 days to complete. In how much time can B alone can do the work?<br />
<br />
( In this question what in initial unit to do work or total work)Quantitative Aptitudehttps://aptitude.gateoverflow.in/4855/self-doubtsTue, 16 Apr 2019 03:54:41 +0000Answered: CAT2001-21
https://aptitude.gateoverflow.in/1288/cat2001-21?show=4846#a4846
<p style="text-align:center"><img alt="" src="https://aptitude.gateoverflow.in/?qa=blob&qa_blobid=7588533691663309127"></p>
<p> </p>
<p>The answer is option 3.</p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/1288/cat2001-21?show=4846#a4846Sat, 30 Mar 2019 11:39:10 +0000Answered: Calculate Reservation Charge
https://aptitude.gateoverflow.in/845/calculate-reservation-charge?show=4843#a4843
Let x be the reservation charge and h be the cost of half ticket. <br />
<br />
From condition 2:<br />
<br />
cost of total full ticket = cost of full ticket + cost of reservation <br />
<br />
400 = cost of full ticket + x<br />
<br />
hence,<br />
<br />
cost of full ticket = 400 – x<br />
<br />
<br />
<br />
From condition 1:<br />
<br />
cost of half ticket = ¾ * cost of full ticket<br />
<br />
= ¾ *(400 - x)<br />
<br />
cost of total half ticket : ¾ *(400 - x) + x<br />
<br />
<br />
<br />
From condition 3:<br />
<br />
Cost of total full ticket + 2*cost of total half ticket = 1050<br />
<br />
400 + 2* (¾ *(400 - x) + x) = 1050<br />
<br />
2* (¾ *(400 - x) + x) = 650<br />
<br />
¾ *(400 - x) + x = 325<br />
<br />
1200 -3x + 4x = 1300<br />
<br />
x = 100Quantitative Aptitudehttps://aptitude.gateoverflow.in/845/calculate-reservation-charge?show=4843#a4843Sat, 23 Mar 2019 20:47:10 +0000Answered: Which company had the widest range of share prices over the 5 years?
https://aptitude.gateoverflow.in/249/which-company-had-the-widest-range-share-prices-over-the-years?show=4840#a4840
<p><strong>Which company had the widest range of share prices over the 5 years?</strong></p>
<p>Pilemin Airlines Share price range 1.45 - 180 = 35p</p>
<p>RentaBanga 1.55 - 170 = 15p</p>
<p>Rupt Bank 0.45 - 1.65 = £1.25</p>
<p>Cash Casinos 0.40 - 1.20 = 80p</p>
<p>Stackem Supermarts 1.55 - 2.00 = 45p</p>
<p> </p>
<p><strong>Which year had the widest range of share prices?</strong></p>
<p>2002 Range 0.4 - 1.95 = 1.55</p>
<p>2003 0.55 - 2.00 = 1.45</p>
<p>2004 0.85 - 1.75 = 0.90</p>
<p>2005 0.75 - 1.85 = 1.10</p>
<p>2006 0.9 - 1.65 = 0.75</p>
<p> </p>
<p><strong>Between 2002 and 2006 what was the approximate total change in share</strong></p>
<p>prices for all companies?</p>
<p>Total share price 2002 = £5.80</p>
<p>Total share price 2006 = 7.20</p>
<p>Percentage increase in price = (Change in price/original price) x 100</p>
<p>= (1.40 / 5.80) x 100 = 24.1% = + 25% to nearest 5%</p>
<p> </p>
<p><strong>If the proportional change in share price for Pilemin Airlines had been the</strong></p>
<p><strong>same as that for Rupt Bank between 2002 and 2006 what would have been the</strong></p>
<p><strong>value of Pilemin Airlines shares in 2006?</strong></p>
<p>Share price for Rupt Bank 2002 = £0.45</p>
<p>Share price for Rupt Bank 2006 = £1.65</p>
<p>Change in share price for Rupt Bank 2002-06 = 1.20 / 0.45 = 266%</p>
<p>Price of Pilemin Airlines shares in 2002 = 1.45</p>
<p>Increase in price of Pilemin Airlines shares 2002 - 2006 = Price in 2002 x Change in</p>
<p>share price for Rupt Bank</p>
<p>1.45 x 2.66 = £3.86</p>
<p>Therefore price in 2006 = original price plus increase in price = £1.45 + £3.86 increase</p>
<p>= £5.31</p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/249/which-company-had-the-widest-range-share-prices-over-the-years?show=4840#a4840Sat, 16 Mar 2019 10:18:01 +0000Answered: made easy cbt 1 2019
https://aptitude.gateoverflow.in/4830/made-easy-cbt-1-2019?show=4836#a4836
Let $s$ and $d$ be the original speed of train and total distance. Therefore,<br />
<br />
$\left ( 50/s \right ) + \left ( d-50 \right )/\left ( 3s/4 \right ) = \left ( d/s \right )+35/60$ ---(1)<br />
<br />
$\left ( 74/s \right ) + \left ( d-74 \right )/\left ( 3s/4 \right ) = \left ( d/s \right )+25/60$ ---(2)<br />
<br />
<br />
<br />
Solving Equation (1) and (2), we get $s$ $=$ $48 km/hr$.Quantitative Aptitudehttps://aptitude.gateoverflow.in/4830/made-easy-cbt-1-2019?show=4836#a4836Sat, 26 Jan 2019 13:47:13 +0000Answered: Amcat
https://aptitude.gateoverflow.in/4834/amcat?show=4835#a4835
<p>LCM of two Fractions is<strong> LCM of Numerators </strong><em>divided by</em> <strong>GCD of Denominators.</strong></p>
<p>LCM of 147 and 30 is 1470</p>
<p>GCD of 64 and 44 is 4</p>
<p>So final Answer is 1470/4 =<strong> 735/2.</strong></p>
<p> </p>
<p>tell me If I am wrong.</p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/4834/amcat?show=4835#a4835Sat, 26 Jan 2019 11:42:26 +0000Answered: CAT2000-108
https://aptitude.gateoverflow.in/1232/cat2000-108?show=4832#a4832
Answer -1192<br />
<br />
To convert an integer to base b, divide it by b. The remainder is the ones place. <br />
<br />
convert 1982 to base 12 ,first 1982 divide by 12 that gives quotient – 165 and remainder- 2 So the number ends in a 2<br />
<br />
again previous quotient divide by base 12 , 165 divide by 12 that gives quotient – 13 and remainder- 9 So the number ends in a 92<br />
<br />
again previous quotient divide by base 12 , 13 divide by 12 that gives quotient – 1 and remainder- 1 So the number ends in a 192<br />
<br />
Finally, 1 is less than 12 so its representation is just 1, <br />
<br />
so result is 1192Quantitative Aptitudehttps://aptitude.gateoverflow.in/1232/cat2000-108?show=4832#a4832Sun, 20 Jan 2019 06:19:11 +0000altitude
https://aptitude.gateoverflow.in/4829/altitude
A son Invest Half of his money in 47 stock at 100 and the other half in 67 at 90:Had he Inverted his money in order to buy Casual Amount of each stock, he would get 210 less of his Income Find his total Investment6100205Quantitative Aptitudehttps://aptitude.gateoverflow.in/4829/altitudeWed, 09 Jan 2019 07:53:09 +0000Answered: GEOMETRY
https://aptitude.gateoverflow.in/4821/geometry?show=4827#a4827
<p>refer <a rel="nofollow" href="https://www.competoid.com/quiz_answers/14-0-57157/Question_answers/">https://www.competoid.com/quiz_answers/14-0-57157/Question_answers/</a></p>
<p>which is similar question</p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/4821/geometry?show=4827#a4827Fri, 21 Dec 2018 05:34:53 +0000Answered: Problem on ages (RS AGGARWAL)
https://aptitude.gateoverflow.in/4707/problem-on-ages-rs-aggarwal?show=4823#a4823
<p>X and y<a rel="nofollow" href="https://aptitude.gateoverflow.in/?qa=blob&qa_blobid=9240160689581224599">https://aptitude.gateoverflow.in/?qa=blob&qa_blobid=9240160689581224599</a></p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/4707/problem-on-ages-rs-aggarwal?show=4823#a4823Mon, 17 Dec 2018 10:34:46 +0000Answered: Probability
https://aptitude.gateoverflow.in/4817/probability?show=4819#a4819
Total number of balls = 8 + 7 + 6 = 21<br />
<br />
Let E be the event of selecting neither red nor green ball<br />
<br />
Then n(E) = 7<br />
<br />
Required probability = 7/21 = 1/3Quantitative Aptitudehttps://aptitude.gateoverflow.in/4817/probability?show=4819#a4819Sat, 08 Dec 2018 06:48:02 +0000Answered: CAT2004-72
https://aptitude.gateoverflow.in/882/cat2004-72?show=4799#a4799
<p>diagonal of cube = √3*a</p>
<p>now since side of triangle is equal to diagonal of cube ; therefore side of triangle =√3*a;</p>
<p>we have to now find radius of circumcircle</p>
<p><strong>circumcircle is the circle in which triangle is inscribed and its radius is a/√3;</strong></p>
<p><strong>incircle is the circle which is inscribed in a triangle and its radius is a/(√3*2);</strong></p>
<p>so, here rad of circumcircle is √3*a/<strong>√3;</strong></p>
<p>hence it is equal to a; ehich is the side of triangle;</p>
<p>hence option A.</p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/882/cat2004-72?show=4799#a4799Sun, 28 Oct 2018 12:43:51 +0000SELF
https://aptitude.gateoverflow.in/4798/self
<p><strong>An oblong piece of ground measures 19m 2.5 dm by 12m5dm.From center of each side of the ground, a path 2m wide goes across to the center of the opposite side. What is the area of the path?</strong></p>
<p>A)59.5 m^2<br>
B)54 m^2<br>
C)78.4 m^2<br>
D)34 m^2</p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/4798/selfSun, 28 Oct 2018 12:12:06 +0000Answered: self doubt
https://aptitude.gateoverflow.in/4724/self-doubt?show=4791#a4791
$A$ can complete half work in $7$ days. So, speed of work of $A = \frac{x}{2\times 7} = \frac{x}{14}$ where $x$ is the amount of work to be done. <br />
<br />
Similarly speed of work of $B = \frac{x}{42}$<br />
<br />
Given that $A$ is doing half the work and $B$ is doing $1/3$ the work. So, remaining work $= 1 - 1/2 - 1/3 = 1/6.$ $C$ can complete $20\%$ of this in $28/5$ days. So,<br />
<br />
speed of work of $C = \frac{0.2 \times 5x}{28 \times 6} = \frac{x}{168}$<br />
<br />
Now, when $A, B$ and $C$ work together, their combined speed will be$ = \frac{x}{14} + \frac{x}{42} + \frac{x}{168} = \dfrac{12x+4x+x}{168} = \dfrac{17x}{168} $<br />
<br />
So, amount of time required $=\dfrac{x}{\frac{17x}{168}} = \dfrac{168}{17}$Quantitative Aptitudehttps://aptitude.gateoverflow.in/4724/self-doubt?show=4791#a4791Thu, 11 Oct 2018 14:46:44 +0000Answered: Ratio and Proportion
https://aptitude.gateoverflow.in/4353/ratio-and-proportion?show=4788#a4788
Let the first part be x then the second part will be (96-x)<br />
<br />
A/q , x / 7 = (96-x)/9<br />
<br />
on solving for x, we will get x = 42<br />
<br />
So, first part will be 42 and the second part will be 54<br />
<br />
clearly the smaller number is 42Quantitative Aptitudehttps://aptitude.gateoverflow.in/4353/ratio-and-proportion?show=4788#a4788Mon, 08 Oct 2018 18:13:12 +0000Answered: Permutation
https://aptitude.gateoverflow.in/4746/permutation?show=4787#a4787
assume you have tied all the women with a rope in order to ensure that they always remain together. Now , we have 5 groups i.e. 4 men and one group of women consisting of 3 women which is tied together.<br />
<br />
We can arrange group of 5 people in 5! ways <br />
<br />
Now, in women group which are tied ,among them 3 different women are there which can be arranged in 3! ways <br />
<br />
Now, both of them have to be together = 5! * 3! = 720Quantitative Aptitudehttps://aptitude.gateoverflow.in/4746/permutation?show=4787#a4787Mon, 08 Oct 2018 18:01:43 +0000Answered: CAT2001-56
https://aptitude.gateoverflow.in/1328/cat2001-56?show=4783#a4783
EADBFCQuantitative Aptitudehttps://aptitude.gateoverflow.in/1328/cat2001-56?show=4783#a4783Sun, 09 Sep 2018 22:34:22 +0000Answered: Geeksforgeeks Sudo Placements
https://aptitude.gateoverflow.in/4775/geeksforgeeks-sudo-placements?show=4777#a4777
profit of 20 pencils at selling cost price<br />
<br />
profit=profit/cost price=20/30=66.66%Quantitative Aptitudehttps://aptitude.gateoverflow.in/4775/geeksforgeeks-sudo-placements?show=4777#a4777Mon, 03 Sep 2018 18:28:13 +0000Answered: Interview Question
https://aptitude.gateoverflow.in/4764/interview-question?show=4774#a4774
A is a stronger player than B so probability of wining A is higher then probability of wining B .<br />
<br />
let W=win L=lost<br />
<br />
Probability of wining A to you = 3/4 , W= 0.75 L=0.25<br />
<br />
Probability of wining B to you = 1/2=0.50 L=0.5<br />
<br />
Case 1: AAB <br />
<br />
probability for you to win series = WWL + LWW+WWW= 0.25*0.25*0.5+0.75*0.25*0.5+0.25*0.25*0.5=0.15625<br />
<br />
Case 2: ABA <br />
<br />
probability for you to win series = WWL + LWW+WWW= 0.25*0.5*0.75+0.75*0.5*0.25+0.25*0.5*0.25=0.21875<br />
<br />
Case 3: BAB<br />
<br />
probability for you to win series = WWL + LWW+WWW=0.5*0.25*0.5+0.5*0.25*0.5+0.5*0.25*0.5=0.1875<br />
<br />
Case 4: BAA<br />
<br />
probability for you to win series = WWL + LWW+WWW=0.15625<br />
<br />
so ABA sequence will maximize our chances to win seriese Ans=2Quantitative Aptitudehttps://aptitude.gateoverflow.in/4764/interview-question?show=4774#a4774Tue, 28 Aug 2018 10:29:01 +0000Answered: CAT 2007-06
https://aptitude.gateoverflow.in/4768/cat-2007-06?show=4773#a4773
<p>1/m+4/n=1/12</p>
<p>(n+4m)/mn=1/12</p>
<p>mn=12(n+4m)=12n+48m ----1</p>
<p>RHS will be even and it is given that n is odd so m should be even(even=even*odd).</p>
<p>n={1,3,5,...,57,59}</p>
<p>m={2,4,6,...,58,60}</p>
<p> by equation 1 we can conclude .. to get positive value of m n>48</p>
<p>so for n=49 </p>
<p> 49m=12*49+48m</p>
<p> <strong> m=588 this is also even </strong></p>
<p>n=51</p>
<p><strong>51m-48m=12*51 => 3m=12*51 => m=204</strong></p>
<p>n=53</p>
<p>5m=12*53=>m=127.2 which is not even integer</p>
<p>n=55</p>
<p>7m=12*55=> m=92.28 which is not even integer</p>
<p>n=57 </p>
<p><strong>9m=12*57=> m=76 this is valid </strong></p>
<p>n=59</p>
<p>11m=12*59=>m=64.3</p>
<p>so number of possible solutions =3</p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/4768/cat-2007-06?show=4773#a4773Tue, 28 Aug 2018 09:46:35 +0000Answered: Clock - Relative speed is also increasing every hour
https://aptitude.gateoverflow.in/4769/clock-relative-speed-is-also-increasing-every-hour?show=4770#a4770
After 30daysQuantitative Aptitudehttps://aptitude.gateoverflow.in/4769/clock-relative-speed-is-also-increasing-every-hour?show=4770#a4770Mon, 13 Aug 2018 12:24:48 +0000Answered: CAT1998-94
https://aptitude.gateoverflow.in/3275/cat1998-94?show=4761#a4761
For remainder of 8, we need to check only last three digits of given no.<br />
<br />
So 354%8=2<br />
<br />
Option (C)Quantitative Aptitudehttps://aptitude.gateoverflow.in/3275/cat1998-94?show=4761#a4761Tue, 31 Jul 2018 08:27:39 +0000Answered: CAT1996-159
https://aptitude.gateoverflow.in/3830/cat1996-159?show=4741#a4741
<p>Here, new technique refers to the design stage is performed in $3,4, \& \hspace{0.1cm} 5^{th} month$ & in the $5^{th}$ month $5$ people are working on the design stage. And the coding stage was finished in $6^{th} - 8^{th}$ months.</p>
<p>The new table will be look like:</p>
<table border="1" cellpadding="1" style="width:90%">
<thead>
<tr>
<th scope="col">Month</th>
<th scope="col">Stage</th>
<th scope="col">Cost(Rs. '000 per man-month)</th>
</tr>
<tr>
<td>$1-2$</td>
<td>Specification</td>
<td>$40$</td>
</tr>
<tr>
<td>$3-5$</td>
<td>Design</td>
<td>
<p>$20$</p>
</td>
</tr>
<tr>
<td>$6-8$</td>
<td>Coding</td>
<td>
<p>$10$</p>
</td>
</tr>
<tr>
<td>$9-10$</td>
<td>Testing</td>
<td>
<p>$15$</p>
</td>
</tr>
<tr>
<td>$11-15$</td>
<td>Maintenance</td>
<td>$10$</td>
</tr>
</thead>
</table>
<p>The number of people employed in each month is:</p>
<table border="1" cellpadding="1" style="width:500px">
<tbody>
<tr>
<th scope="row">Month</th>
<td>$1$</td>
<td>$2$</td>
<td>$3$</td>
<td>$4$</td>
<td>$5$</td>
<td>$6$</td>
<td>$7$</td>
<td>$8$</td>
<td>$9$</td>
<td>$10$</td>
<td>$11$</td>
<td>$12$</td>
<td>$13$</td>
<td>$14$</td>
<td>$15$</td>
</tr>
<tr>
<th scope="row">No. of people employed</th>
<td>$2$</td>
<td>$3$</td>
<td>$4$</td>
<td>$3$</td>
<td>$5$</td>
<td>$5$</td>
<td>$5$</td>
<td>$4$</td>
<td>$4$</td>
<td>$1$</td>
<td>$3$</td>
<td>$3$</td>
<td>$1$</td>
<td>$1$</td>
<td>
<p>$1$</p>
</td>
</tr>
</tbody>
</table>
<p>We can clearly see that, the maintenance stage has the lowest average cost per man-month .</p>
<p>In the $1-5$ month span,</p>
<p>average cost per man-month in $1-2$ month is $40,000$</p>
<p>average cost per man-month in $3-5$ month is $20,000$</p>
<p>So, average cost per man-month in $1-5$ month is = $\dfrac{(40,000+20,000)}{2} = 30,000$</p>
<p>In the $9-13$ month span,</p>
<p>avg. cost per man-month in $9-10$ month is $15,000$</p>
<p>avg. cost per man-month is $10-13$ month is $10,000$</p>
<p>So, avg. cost per man-month in $9-13$ month is $\dfrac{(15,000+10,000)}{2} = 12,500$</p>
<p>In the $11-15$ month span, average cost per man-month is $10,000$</p>
<p>So, the $11-15$ month span will be having lowest average cost per man-month under the new technique.</p>
<p><strong>Answer is option C)</strong></p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/3830/cat1996-159?show=4741#a4741Mon, 02 Jul 2018 08:51:13 +0000Answered: CAT1996-156
https://aptitude.gateoverflow.in/3827/cat1996-156?show=4740#a4740
If the coding stage was performed in the $5^{th}$ month, then the cost will be $10,000 $ per man-month which is $10,000 \times 4 = 40,000$ because the coding stage was supposed to perform by $4$ people.<br />
<br />
But,<br />
<br />
now the design stage is performed in the $5^{th}$ month & $5$ people are working on that stage and for performing or doing the design stage the cost is $20,000$ per man-month, & the total cost will be $20,000 \times 5 = 1,00,000$ in the $5^{th}$ month.<br />
<br />
In the $5^{th}$ month, the cost was supposed to be $40,000$<br />
<br />
& now the cost incurred = $1,00,000$<br />
<br />
Percentage change in the cost incurred in the $5^{th}$ month = $\dfrac{(1,00,000-40,000)}{40,000} \times 100\% \\ = \dfrac{60,000}{40,000} \times 100\% \\ = \dfrac{6}{4} \times 100\% \\ = \dfrac{3}{2} \times 100\% \\ = 150\%$Quantitative Aptitudehttps://aptitude.gateoverflow.in/3827/cat1996-156?show=4740#a4740Mon, 02 Jul 2018 06:41:52 +0000Answered: CAT1996-167
https://aptitude.gateoverflow.in/3838/cat1996-167?show=4736#a4736
C=MarchQuantitative Aptitudehttps://aptitude.gateoverflow.in/3838/cat1996-167?show=4736#a4736Wed, 27 Jun 2018 08:13:34 +0000Answered: madeeasy work book
https://aptitude.gateoverflow.in/4714/madeeasy-work-book?show=4718#a4718
Assuming, its usual speed is $x \hspace{0.1cm} km/hr $<br />
<br />
∴ New Speed will be $= x+ 33.33\% \hspace{0.1cm} of \hspace{0.1cm} x \\ = x+ \dfrac{1}{3} \text{ of x } \\ = \dfrac{4x}{3} \hspace{0.1cm} km/hr$<br />
<br />
In $x \hspace{0.1cm} km/hr$ speed $1500 \hspace{0.1cm} km$ can be covered in $\dfrac{1500}{x} \hspace{0.1cm} hr$ $\qquad \left [ \because Distance = Speed \times Time \\ \qquad \qquad Or, Time = \dfrac{Distance}{Speed}\right ]$<br />
<br />
Now In $\dfrac{4x}{3} km/hr$ speed $1500 \hspace{0.1cm} km$ can be covered in $\dfrac{1500}{\dfrac{4x}{3}} = \dfrac{1500 \times 3}{4x} \hspace{0.1cm} hr$<br />
<br />
As the plane lates for half an hour, the difference between the usual time taken by the plane and time taken by plane in new speed will be half an hour.<br />
<br />
$∴\dfrac{1500}{x} - \dfrac{1500 \times 3}{4x} = \dfrac{1}{2}$<br />
<br />
Or, $\dfrac{(1500 \times 4) - (1500 \times 3)}{4x} = \dfrac{1}{2}$<br />
<br />
Or. $\dfrac{6000 - 4500}{4x} = \dfrac{1}{2}$<br />
<br />
Or, $\dfrac{1500}{4x} = \dfrac{1}{2}$<br />
<br />
Or, $4x = 1500 \times 2$<br />
<br />
Or, $x = \dfrac{3000}{4} = 750\hspace{0.1cm} km/hr$<br />
<br />
So, the plane's usual speed is $750\hspace{0.1cm} km/hr$<br />
<br />
∴ New speed will be $\dfrac{4x}{3}$ i.e. $\dfrac{4 \times 750}{3} = 1000 \hspace{0.1cm} km/hr$<br />
<br />
∴ The plane's usual speed is $750 \hspace{0.1cm} km/hr$ & New speed is $1000 \hspace{0.1cm} km/hr$ which means the plane increases its speed by $250 \hspace{0.1cm} km/hr$ than its ususal speed to make up the timing .Quantitative Aptitudehttps://aptitude.gateoverflow.in/4714/madeeasy-work-book?show=4718#a4718Sat, 09 Jun 2018 13:51:48 +0000Answered: How to solve this?
https://aptitude.gateoverflow.in/4704/how-to-solve-this?show=4706#a4706
$x+\dfrac{1}{x} = 4$<br />
<br />
squaring on both sides , we get -<br />
<br />
Or, $\left (x+\dfrac{1}{x} \right)^2 = 4^2$<br />
<br />
Or, $x^2+\left (\dfrac{1}{x} \right )^2 + 2.x.\dfrac{1}{x} = 16$<br />
<br />
Or, $x^2+\left (\dfrac{1}{x} \right )^2 + 2 = 16$<br />
<br />
Or, $x^2+\dfrac{1}{x^2}= 16-2 = 14$ ------------------1)<br />
<br />
Now, we'll cubing on both sides-<br />
<br />
$\left (x^2+\dfrac{1}{x^2} \right)^3 = (14)^3$<br />
<br />
Or, $ (x^2)^3+\left(\dfrac{1}{x^2}\right)^3 + 3.(x^2)^2.\dfrac{1}{x^2}+3.x^2.\left(\dfrac{1}{x^2}\right)^2 = (14)^3 = 2744$ $ \color{purple}{\left [\because (a+b)^3 = a^3+b^3+3a^2b+3ab^2 \right ]}$<br />
<br />
Or, $ x^{2 \times 3}+\left(\dfrac{1}{x^{2 \times 3}}\right) + 3.x^{2 \times 2}.\dfrac{1}{x^2}+3.x^2.\left(\dfrac{1}{x^{2 \times 2}}\right) =2744$ <br />
<br />
Or, $x^{6}+\dfrac{1}{x^{6}} + 3.x^{4}.\dfrac{1}{x^2}+3.x^2.\dfrac{1}{x^{4}}=2744$<br />
<br />
Or, $x^{6}+\dfrac{1}{x^{6}} + 3.x^{2}+3.\dfrac{1}{x^{2}}=2744$<br />
<br />
Or, $x^{6}+\dfrac{1}{x^{6}} + 3\left (x^{2}+\dfrac{1}{x^{2}} \right )=2744$<br />
<br />
Or, $x^{6}+\dfrac{1}{x^{6}} + 3\left (14 \right )=2744$ $ \qquad \qquad \left [ \color{Blue }{ \because \text{We know,} \left (x^{2}+\dfrac{1}{x^{2}} \right ) = 14} \color{teal}{\text{ ----from 1)} }\right ]$<br />
<br />
Or, $x^{6}+\dfrac{1}{x^{6}} + 42 = 2744$<br />
<br />
Or, $\color{Green}{x^{6}+\dfrac{1}{x^{6}}} = 2744-42 = \color{pink}{2702}$Quantitative Aptitudehttps://aptitude.gateoverflow.in/4704/how-to-solve-this?show=4706#a4706Tue, 05 Jun 2018 23:38:35 +0000Answered: CAT1996-162
https://aptitude.gateoverflow.in/3833/cat1996-162?show=4703#a4703
<p>Total Investment in Chittoor in $\text{1995 & 1996 =} (2981.1+3489.5) \\ \qquad \qquad = Rs. \hspace{0.1cm}6470.6$ </p>
<p>Total Investment in Khammam in $\text{1995 & 1996 =} (7081.6+ 8352.0) \\ \qquad \qquad = Rs. \hspace{0.1cm}15433.6$ </p>
<p>∴ <strong>Total investment in Khammam is</strong> $\left \{ \dfrac{15433.6}{6470.6} = 2.3851 \approx 2.4 \right \}$ <strong>times the total investment in Chittoor in the given two years.</strong></p>
<p><strong>∴ Answer is Option C)</strong></p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/3833/cat1996-162?show=4703#a4703Tue, 05 Jun 2018 16:47:59 +0000Answered: CAT1996-165
https://aptitude.gateoverflow.in/3836/cat1996-165?show=4702#a4702
<p>Total investment in Khammam in $1995 = 7081.6$</p>
<p>Total investment in Khammam in $1996 = 8352$</p>
<p>∴ Percentage increase of investment in Khammamin $1995-96 = \dfrac{8352-7081.6}{7081.6} = \dfrac{1270.4}{7081.6} = 0.1793 \hspace{0.2cm}i.e. 17.93\%$</p>
<p>Now, in 1997 $\{ 8352 \times 17.93\% = 1497.5136 \hspace{0.1cm} Rs. \}$ extra will be given to Khammam District than 1996</p>
<p>So, total investment in $1997$ will be $(8352+1497.5136 =)Rs. \hspace{0.1cm}9849.5136 \approx Rs. \hspace{0.1cm}9850$ </p>
<p><strong>∴ Answer will be Option A)</strong></p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/3836/cat1996-165?show=4702#a4702Tue, 05 Jun 2018 16:18:08 +0000Answered: CAT1996-164
https://aptitude.gateoverflow.in/3835/cat1996-164?show=4701#a4701
<p>The following calculations worked for Khammam District </p>
<p>In Electricity area, the percentage increase of investment in $1996$ that of $1995$ is = $\dfrac{(2365.1-2065.8)}{2065.8}\% =\dfrac{299.3}{2065.8}\% = 14.48\% $</p>
<p>In Chemical area, the percentage increase of investment in $1996$ that of $1995$ is = $\dfrac{(986.4-745.5)}{745.5}\% =\dfrac{240.9}{745.5}\% = 32.31\% $</p>
<p>In Solar area, the percentage increase of investment in $1996$ that of $1995$ is = $\dfrac{(1792.1-1363.5)}{1363.5}\% =\dfrac{428.6}{1363.5}\% =31.43\% $</p>
<p>In Nuclear area, the percentage increase of investment in $1996$ that of $1995$ is = $\dfrac{(2182.1-1674.3)}{1674.3}\% =\dfrac{507.8}{1674.3}\% = 30.32\% $</p>
<p><strong>∴ Electricity area in $1996$ showed the least percent increase over the investment in that area in $1995$.</strong></p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/3835/cat1996-164?show=4701#a4701Thu, 31 May 2018 21:31:21 +0000Answered: CAT1996-163
https://aptitude.gateoverflow.in/3834/cat1996-163?show=4700#a4700
In $1995$,<br />
<br />
Investment in Electricity in Chittoor= $815.2$ Rs.<br />
<br />
Investment in Electricity in Khammam= $2065.8$ Rs. <br />
<br />
Investment in Thermal Energy in Chittoor= $690.4$ Rs.<br />
<br />
Investment in Thermal Energy in Khammam= $1232.7$ Rs.<br />
<br />
∴ Total investment in Electricity & Thermal Energy in $1995$ = $815.2 + 2065.8 + 690.4 + 1232.7 = 4804.1$ Rs.<br />
<br />
∴ Total investment in Electricity & Thermal Energy in $1995$ are of a total of $\left [ \dfrac{4804.1}{2981.1+7081.6}\% \right ] = 47.74\% $ of the total investment made in these two districts (Chittoor & Khammam) in $1995$.Quantitative Aptitudehttps://aptitude.gateoverflow.in/3834/cat1996-163?show=4700#a4700Thu, 31 May 2018 21:11:43 +0000Answered: CAT1996-161
https://aptitude.gateoverflow.in/3832/cat1996-161?show=4699#a4699
<p>Total investment in $1995 = \left (2981.1 + 7081.6 \right) = 10062.7 \hspace{0.1cm}Rs.$</p>
<p>Whereas, Total investment in $1996 = \left (3489.5 + 8352.0 \right) = 11841.5 \hspace{0.1cm}Rs. $</p>
<p>∴ Total investment of $1996$ is $\left [\dfrac{(11841.5-10062.7)}{10062.7} = 0.1767 \hspace{0.1cm} \right ] i.e. \hspace{0.1cm} 17.67\%$ greater than the total investment of $1995$.</p>
<p>∴ <strong>The answer will be <em>Option D )</em></strong></p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/3832/cat1996-161?show=4699#a4699Thu, 31 May 2018 21:00:57 +0000Answered: CAT1996-168
https://aptitude.gateoverflow.in/3839/cat1996-168?show=4697#a4697
<p>In the month of March, Sales is = $35$, whereas, in Jan, Sales is = $30$</p>
<p>∴ Percentage increase = $\dfrac{35-30}{30}\% = \dfrac{5}{30}\% = 16.66\%$</p>
<p>In the month of September, Sales is = $39$, whereas, in July, Sales is = $36$</p>
<p>∴ Percentage increase = $\dfrac{39-36}{36}\% = \dfrac{3}{36}\% = 8.33\%$</p>
<p>In the month of July, Sales is = $36$, whereas, in May, Sales is = $36$</p>
<p>∴ Percentage increase = $0\%$</p>
<p>In the month of May, Sales is = $36$, whereas, in March, Sales is = $35$</p>
<p>∴ Percentage increase = $\dfrac{36-35}{35}\% = \dfrac{1}{35}\% = 2.85\%$</p>
<p><strong>∴</strong> <strong>In March, the percentage increases in Sales two months before, the highest (which is</strong> $16.66\%$)</p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/3839/cat1996-168?show=4697#a4697Thu, 31 May 2018 13:10:52 +0000Answered: CAT1996-170
https://aptitude.gateoverflow.in/3841/cat1996-170?show=4696#a4696
<p>As nothing is mentioned about employee number is in hundred or in thousand, I'm assuming it is in thousand (by seeing the given options)</p>
<p>In Jan, the total number of employees are $10$</p>
<p>Whereas, in Nov, the total number of employees is $16$</p>
<p>So, in the given period means from Jan-Nov Company takes a total of $(16-10)= 6$ which means $6,000$ employees.</p>
<p>And, among the given options the closest number of $6000$ is $5800$ which is Option C)</p>
<p>∴<strong> Answer is Option C)</strong></p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/3841/cat1996-170?show=4696#a4696Thu, 31 May 2018 12:32:33 +0000Answered: CAT1996-169
https://aptitude.gateoverflow.in/3840/cat1996-169?show=4695#a4695
<p>In March Cost is = $30$, whereas in Jan Cost is = $29$</p>
<p>So, the difference between cost is = $(30-29)= 1$</p>
<p>In May Cost is = $34$ , whereas in March cost is = $30$</p>
<p>So, the difference between cost is = $(34-30)= 4$</p>
<p>In July Cost is = $35$ , whereas in May cost is = $34$</p>
<p>So, the difference between cost is = $(35-34)= 1$</p>
<p>In September Cost is = $37$ , whereas in July cost is = $35$</p>
<p>So, the difference between cost is = $(37-35)= 2$</p>
<p><strong>∴ In May the total increase in the Cost highest as compared to the Cost two months ago</strong></p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/3840/cat1996-169?show=4695#a4695Thu, 31 May 2018 12:14:27 +0000#GeeksforGeeks
https://aptitude.gateoverflow.in/4685/%23geeksforgeeks
<p>Q. A vessel is filled with a solution of, 3 parts soda and 5 parts rum. How much of the solution must be taken out and replaced with soda so that the solution contains equal amount of sod and rum?<br>
<strong>(A)</strong> 8/5<br>
<strong>(B)</strong> 2/5<br>
<strong>(C)</strong> 1/5<br>
<strong>(D)</strong> 5/8</p>Quantitative Aptitudehttps://aptitude.gateoverflow.in/4685/%23geeksforgeeksMon, 21 May 2018 17:43:04 +0000How to Prepare for Quantitatve Aptitude, Chapter: Number System, Topic: HCF & LCM
https://aptitude.gateoverflow.in/4672/prepare-quantitatve-aptitude-chapter-number-system-topic
Which of the following represents the largest 4 digit number which can be added to 7249 in order to make the derived number divisible by each of 12, 14, 21, 33, and 54.<br />
<br />
(a) 9123<br />
<br />
(b) 9383<br />
<br />
(c) 8727<br />
<br />
(d) None of theseQuantitative Aptitudehttps://aptitude.gateoverflow.in/4672/prepare-quantitatve-aptitude-chapter-number-system-topicSun, 13 May 2018 09:10:14 +0000ages
https://aptitude.gateoverflow.in/4560/ages
<table>
<tbody>
<tr>
<td colspan="2"> Ten years ago, P was half of Q's age. If the ratio of their present ages is 3:43:4, what will be the total of their present ages?</td>
</tr>
<tr>
<td>A. 4545</td>
<td>B. 4040</td>
</tr>
<tr>
<td>C. 3535</td>
<td>D. 30</td>
</tr>
</tbody>
</table>Quantitative Aptitudehttps://aptitude.gateoverflow.in/4560/agesSun, 28 Jan 2018 02:30:22 +0000ratio
https://aptitude.gateoverflow.in/4559/ratio
Q.Rekha and Kallu have a certain number of red and black marbles with them. The ratio of red marbles to black marbles with them is 7 : 1 and 9 : 1 respectively. If the total number of marbles with the two persons is 90, what can be the number of red marbles with Kallu?<br />
a.Either 9 or 45 b.Either 10 or 50 c.Either 36 or 72 d.Either 18 or 36Quantitative Aptitudehttps://aptitude.gateoverflow.in/4559/ratioSun, 28 Jan 2018 02:29:24 +0000self doubt
https://aptitude.gateoverflow.in/4558/self-doubt
Q.How many four-digit numbers, with distinct digits are there such that the sum of the digits of each of these numbers is an odd natural number?<br />
a.2160 b.2090 c.1880 d.2376Quantitative Aptitudehttps://aptitude.gateoverflow.in/4558/self-doubtSun, 28 Jan 2018 02:28:35 +0000p(p−1)<0 what is value of p
https://aptitude.gateoverflow.in/4547/p-p%E2%88%921-0-what-is-value-of-p
p(p−1)<0 what is value of p please solve step by step <br />
<br />
options are <br />
<br />
(A) (–∞, 0)<br />
(B) (0, 1)<br />
(C) (1, ∞)<br />
(D) (0, ∞)Quantitative Aptitudehttps://aptitude.gateoverflow.in/4547/p-p%E2%88%921-0-what-is-value-of-pWed, 10 Jan 2018 04:09:48 +0000clocks
https://aptitude.gateoverflow.in/4543/clocks
Find the angle between hands of clock at 2:30 p.m in degressQuantitative Aptitudehttps://aptitude.gateoverflow.in/4543/clocksTue, 09 Jan 2018 11:05:48 +0000Time and distance
https://aptitude.gateoverflow.in/4542/time-and-distance
Car A left from X for Y at 9:00 a.m.Car B left from Y to X at 10:00 a.m.XY=180 km.<br />
<br />
Speed of A and B are 30 and 20 kmph respectively.Find their meeting timeQuantitative Aptitudehttps://aptitude.gateoverflow.in/4542/time-and-distanceTue, 09 Jan 2018 10:59:35 +0000percentage
https://aptitude.gateoverflow.in/4531/percentage
Ravi's salary before he got an increment was 20% of total income of of his family.His increment was one fourth of his salary after increment.What percentage of total income of his family is his new salaryQuantitative Aptitudehttps://aptitude.gateoverflow.in/4531/percentageTue, 26 Dec 2017 08:33:52 +0000ratio and proposition
https://aptitude.gateoverflow.in/4526/ratio-and-proposition
X,Y and Z are 3 quantities.X varies inversely with Y when z is constant.Y varies inversely with Z when X is constant.When Y=8,Z=7 and X=30.Find X if Y=16 and Z=21Quantitative Aptitudehttps://aptitude.gateoverflow.in/4526/ratio-and-propositionMon, 25 Dec 2017 00:20:41 +0000