1 votes 1 votes Suppose $\mathrm{k}$ is any integer such that the equation $2 x^{2}+k x+5=0$ has no real roots and the equation $x^{2}+(k-5) x+1=0$ has two distinct real roots for $\mathrm{x}$. Then, the number of possible values of $\mathrm{k}$ is $7$ $9$ $8$ $13$ Quantitative Aptitude cat2022-set3 + – admin asked Mar 3, 2023 • edited Dec 30, 2023 by makhdoom ghaya admin 4.5k points 275 views answer comment Share See all 0 reply Please log in or register to add a comment.