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A quadratic function $ƒ(x)$ attains a maximum of $3$ at $x = 1$. The value of the function at $x = 0$ is $1$. What is the value $ƒ(x)$ at $x = 10$? 

  1. $–119$ 
  2. $–159$ 
  3. $–110$ 
  4. $–180$
asked in Logical Reasoning by (7.8k points) 59 191 507 | 28 views

1 Answer

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b is correct ans.

process to solve; fisrst let the quadratic equation be ax^2 + bx + c

and x=0 as it is given from here we found c=1.

and by putting x=1 we find a+b=2

now final task as clu is given in question that max at x=1 is three so we all know maxima happens at x= – b^2 /4a

so putting it into initial equation we find relation b^2 = -8a so now using this into a+b=2 we found a quaratic like

(b-4)^2=0 so b=4 and a=-2 by putting all these values in first we found -2x^2+4x+1.

hence at x=10 value is -159.

note: if u dont know quadratic equation maximum better use derivative concept of finding maxima and minima.
answered by (26 points)

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