makhdoom ghaya
asked
in Quantitative Aptitude
Jan 17, 2016
recategorized
Mar 25, 2022
by Lakshman Patel RJIT

386 views
0 votes

b is correct ans.

process to solve; fisrst let the quadratic equation be ax^2 + bx + c

and x=0 as it is given from here we found c=1.

and by putting x=1 we find a+b=2

now final task as clu is given in question that max at x=1 is three so we all know maxima happens at x= – b^2 /4a

so putting it into initial equation we find relation b^2 = -8a so now using this into a+b=2 we found a quaratic like

(b-4)^2=0 so b=4 and a=-2 by putting all these values in first we found -2x^2+4x+1.

hence at x=10 value is -159.

note: if u dont know quadratic equation maximum better use derivative concept of finding maxima and minima.

process to solve; fisrst let the quadratic equation be ax^2 + bx + c

and x=0 as it is given from here we found c=1.

and by putting x=1 we find a+b=2

now final task as clu is given in question that max at x=1 is three so we all know maxima happens at x= – b^2 /4a

so putting it into initial equation we find relation b^2 = -8a so now using this into a+b=2 we found a quaratic like

(b-4)^2=0 so b=4 and a=-2 by putting all these values in first we found -2x^2+4x+1.

hence at x=10 value is -159.

note: if u dont know quadratic equation maximum better use derivative concept of finding maxima and minima.