recategorized by
824 views

1 Answer

0 votes
0 votes
b is correct ans.

process to solve; fisrst let the quadratic equation be ax^2 + bx + c

and x=0 as it is given from here we found c=1.

and by putting x=1 we find a+b=2

now final task as clu is given in question that max at x=1 is three so we all know maxima happens at x= – b^2 /4a

so putting it into initial equation we find relation b^2 = -8a so now using this into a+b=2 we found a quaratic like

(b-4)^2=0 so b=4 and a=-2 by putting all these values in first we found -2x^2+4x+1.

hence at x=10 value is -159.

note: if u dont know quadratic equation maximum better use derivative concept of finding maxima and minima.

Related questions

0 votes
0 votes
1 answer
2
makhdoom ghaya asked Jan 16, 2016
509 views
If $y = f(x)$ and $f(x) = (1 - x) / (1 + x)$, which of the following is true? $f(2x) = f(x) – 1$ $x = f(2y) - 1$ $f(1/x) = f(x)$ $x = f(y)$