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$\text{ABC}$ forms an equilateral triangle in which $\text{B}$ is $2$ km from $\text{A}$. A person starts walking from $\text{B}$ in a direction parallel to $\text{AC}$ and stops when he reaches a point $\text{D}$ directly east of $\text{C}$. He, then, reverses direction and walks till he reaches a point $\text{E}$ directly south of $\text{C}$. Then $\text{D}$ is 

  1. $3$ km east and $1$ km north of $\text{A}$ 
  2. $3$ km east and $3$ km north of $\text{A}$ 
  3. $3$ km east and $1$ km south of $\text{A}$ 
  4. $3$ km west and $3$ km north of $\text{A}$
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