523 views

$\text{ABC}$ forms an equilateral triangle in which $\text{B}$ is $2$ km from $\text{A}$. A person starts walking from $\text{B}$ in a direction parallel to $\text{AC}$ and stops when he reaches a point $\text{D}$ directly east of $\text{C}$. He, then, reverses direction and walks till he reaches a point $\text{E}$ directly south of $\text{C}$. Then $\text{D}$ is

1. $3$ km east and $1$ km north of $\text{A}$
2. $3$ km east and $3$ km north of $\text{A}$
3. $3$ km east and $1$ km south of $\text{A}$
4. $3$ km west and $3$ km north of $\text{A}$