0 votes
0 votes

If $x + \dfrac{1}{x} = 99,$ then the value of $\dfrac{100x}{2x^{2} + 102x + 2}$ is :

  1. $1/3$
  2. $1/99$
  3. $99/100$
  4. $3$
in Quantitative Aptitude edited by
12.0k points
33 views

1 Answer

0 votes
0 votes
Given that; $\frac{100x}{2x^2+102x+2}$

Taking $2x$ as common from the denominator we get;

$\implies \frac{100x}{2x(x+51+1/x)}$

$\implies \frac{50}{99+51}=1/3$ [$\because x+\frac{1}{x}=99$]

Option (A) is correct.
4.7k points

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true