0 votes
0 votes

If $x = 5/12, y = – 3/4, z = 1/3,$ the value of $x^{3} + y^{3} + z^{3}$ is :

  1. $-15/16$
  2. $-3/4$
  3. $-9/4$
  4. $-5/16$
in Quantitative Aptitude edited by
12.0k points
33 views

1 Answer

0 votes
0 votes

We know that: $(x+y+z)^3=x^3+y^3+z^3+3(x+y)(y+z)(z+x)…...(i)$

Given that: $x=\frac{5}{12},y=\frac{-3}{4},z=\frac{1}{3}$

  • $(x+y)=\frac{5-9}{12}=-1/3$
  • $(y+z)=\frac{-9+4}{12}=-5/12$
  • $(z+x)=\frac{4+5}{12}=3/4$

Put all these value in equation (I), we get:

$\implies0=x^3+y^3+z^3+3*(-1/3)*(-5/12)*3/4$

$\implies x^3+y^3+z^3=\frac{-5}{16}$

Option $(D)$ is correct.

4.7k points

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true