in Quantitative Aptitude edited by
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If $60 \%$ of $(x-y) = 30 \%$ of $(x+2y),$ then what percent of $x$ is $y?$

  1. $10 \%$
  2. $15 \%$
  3. $20 \%$
  4. $25 \%$
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Given that: $60 \%(x-y)=30 \%(x+2y)$

$\implies 0.6(x-y)=0.3(x+2y)$

$\implies 2(x-y)=(x+2y)$

$\implies 2x-2y=x+2y$

$\implies x=4y\implies y=\frac{x}{4}\times\frac{100}{x}=25\%$

Option (D) is correct.
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