Let’s assume that first number is $x$, second number is $x/2$ third number is $x/3$.
Now according to the given questions
$\implies\frac{x+\frac{x}{2}+\frac{x}{3}}{3}=88$
$\implies \frac{6x+2x+3x}{6}=88*3$
$\implies 11x=88*18$
$\implies x=144$
therefore
- first number =$144$
- second number =$72$
- third number= $48$
So the difference between the second and third numbers is =$72-48=24$
Option $(A)$ is correct.