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If $\dfrac{1}{5}$ of $645 + 7\dfrac{1}{3}$ of $33 – 3\dfrac{3}{4}$ of $x + 109 = 0$ then $x = \; :$

1. $124$
2. $120$
3. $114$
4. None of these

Given:$\frac{1}{5}\times 645+\frac{22}{3}\times 33-\frac{15x}{4}+109=0$

$\implies 129+242-\frac{15x}{4}+109=0$

$\implies-\frac{15x}{4}=-480$

$\implies x=\frac{480\times 4}{15}=128$

Option (D) is correct.
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