edited by
1,996 views

1 Answer

Best answer
3 votes
3 votes

$10^{10}$ < n < $10^{11}$

As the sum of the digits of n = 2, n can be any one out of

11000000000

10100000000

10010000000
.
.
.
10000000001 … (10 such numbers)

or n can be 20000000000

There are 11 such values of n.

 

Hence,Option(1)11 is the correct choice.

selected by

Related questions

0 votes
0 votes
0 answers
1
go_editor asked Jan 13, 2016
411 views
The remainder, when $(15^{23} + 23^{23})$ is divided by $19,$ is$4$$15$$0$$18$
0 votes
0 votes
1 answer
2
0 votes
0 votes
1 answer
4
2 votes
2 votes
1 answer
5
go_editor asked Apr 1, 2016
678 views
Let $n$ be the number of different $5$ digit numbers, divisible by $4$ with the digits $1, 2, 3, 4, 5$ and $6,$ no digit being repeated in the numbers. What is the value ...