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Sum of given n terms in AP is = $n/2(2a+(n-1)d)$ , where n = no of term , a = intial term value , d = common difference

according to given question sum of 11 terms in AP = sum of 19 terms in AP

$11/2(2a+10d) = 19/2(2a+18d)$

$22a+110d=38a+342d$

$16a+232d =0$ ------ (1)

similar sum of 30 term in AP = $30/2(2a+29d)$

multiply by 8 this , we get = $30/2(16a+232d)$

from equation 1 , sum of 30 term in AP = $30/2(0)$ = $0$

So ans is option 1) =0

according to given question sum of 11 terms in AP = sum of 19 terms in AP

$11/2(2a+10d) = 19/2(2a+18d)$

$22a+110d=38a+342d$

$16a+232d =0$ ------ (1)

similar sum of 30 term in AP = $30/2(2a+29d)$

multiply by 8 this , we get = $30/2(16a+232d)$

from equation 1 , sum of 30 term in AP = $30/2(0)$ = $0$

So ans is option 1) =0