retagged by
509 views

1 Answer

1 votes
1 votes

Let the side of hexagon be $x \; \text{cm}.$

The area of regular hexagon $ = 6 \times \frac{\sqrt{3}}{4} x^{2}$

Now, $6 \times  \frac{\sqrt{3}}{4} x^{2} = \frac{\sqrt{3}}{4} (12)^{2}$

$ \Rightarrow 6x^{2} = 12 \times 12 $

$\Rightarrow x^{2} = 24 $

$ \Rightarrow x = \sqrt{24}$

$ \Rightarrow \boxed{ x = 2 \sqrt{6} \; \text{cm}}$

Correct Answer $: \text{B}$


$\textbf{PS:}$ The regular hexagon



The $\triangle \text{ABC}$ are equilateral triangle.

  • The area of an equilateral triangle $ = \frac{\sqrt{3}}{4} \times \text{(Side)}^{2}$
  • The area of regular hexagon $ = 6 \times \frac{\sqrt{3}}{4} \times \text{(Side)}^{2}$
edited by
Answer:

Related questions

1 votes
1 votes
1 answer
1
soujanyareddy13 asked Jan 19, 2022
1,292 views
Suppose the length of each side of a regular hexagon $\text{ABCDEF}$ is $2 \; \text{cm}.$ It $\text{T}$ is the mid point of $\text{CD},$ then the length of $\text{AT, in ...
1 votes
1 votes
1 answer
2
1 votes
1 votes
1 answer
3
soujanyareddy13 asked Jan 19, 2022
745 views
How many three-digit numbers are greater than $100$ and increase by $198$ when the three digits are arranged in the reverse order?
1 votes
1 votes
1 answer
5
soujanyareddy13 asked Jan 19, 2022
631 views
The natural numbers are divided into groups as $(1), (2,3,4), (5,6,7,8,9), \dots $ and so on. Then, the sum of the numbers in the $15 \text{th}$ group is equal to $6090$$...