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Two alcohol solutions, $\text{A}$ and $\text{B},$ are mixed in the proportion $1:3$ by volume. The volume of the mixture is then doubled by adding solution $\text{A}$ such that the resulting mixture has $72\%$ alcohol. If solution $\text{A}$ has $60\%$ alcohol, then the percentage of alcohol in solution $\text{B}$ is

1. $94\%$
2. $92\%$
3. $90\%$
4. $89\%$

1
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