Two alcohol solutions, $\text{A}$ and $\text{B},$ are mixed in the proportion $1:3$ by volume. The volume of the mixture is then doubled by adding solution $\text{A}$ such that the resulting mixture has $72\%$ alcohol. If solution $\text{A}$ has $60\%$ alcohol, then the percentage of alcohol in solution $\text{B}$ is
- $94\%$
- $92\%$
- $90\%$
- $89\%$