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Consider the triangle $\text{ABC}$ shown in the following figure where $\text{BC = 12 cm, DB =9 cm, CD=6 cm,}$ and $\angle \text{BCD} = \angle \text{BAC}.$ What is the ratio of the perimeter of the triangle $\text{ADC}$ to that of the triangle $\text{BDC}?$

  1. $7/9$
  2. $8/9$
  3. $6/9$
  4. $5/9$
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