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CAT 2005 | Question: 01

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$16^{3}$ = 4096 
$17^{3}$=  4913 
$18^{3}$ = 5832 
$19^{3}$ = 6859 

$\frac{(4096+4913+5832+6859)}{70}$ = $\frac{(2170)}{70}$  = 310 

Hence (1).0 is the Answer.

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