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$\log_{y}x$ = a

$\frac{\log (x)}{\log (y)}$ = a ---------(P)

$\log_{z}y$ = b

$\frac{\log(y)}{\log( z)}$ = b ---------(Q)

If we multiply eqn P and Q the we get,

$\frac{\log (x)}{\log (z)}$ = ab ---------(R)

and we are given,

$\log_{x}z$ = b

$\frac{\log (z)}{\log (x)}$ = ab

from eqn R,

$\frac{1}{ab}$ = ab.

If we put a=2 and b=2 then the above equation does not satisfy where as all other options satisfy the equation.

**Ans- 5. (2,2) **