Here we have restriction on 1st and 2nd task.
For 2nd task we have only 2 choices.
For 1st task we have total - 4 choices, { ecxept 1 and {3 or 4} }
For 3rd task we will have total - 4 choices. { except who are assigned to task 1 and 2}
Similaly, for 4th task - 3 choices.
for 5th task - 2 choices.
for 6th task - 1 choices.
So total possibilities of task assignment = 4 * 2 * 4 * 3 * 2 * 1 = 192.
Ans. - 3.