in Quantitative Aptitude edited by
488 views
0 votes
0 votes

Arun, Barun and Kiranmala start from the same place and travel in the same direction at speeds of $30, 40$ and $60$ km per hour respectively. Barun starts two hours after Arun. If Barun and Kiranmala overtake Arun at the same time instant, How many hours after Arun did Kiranmala start?

  1. $3$
  2. $3.5$
  3. $4$
  4. $4.5$
  5. $5$
in Quantitative Aptitude edited by
13.4k points
488 views

1 Answer

2 votes
2 votes
Best answer

Arun has travelled 60 km when Barun starts.

Barun overtakes Arun in $\frac{60}{40-30}$ = 6 hrs

In this time, Barun travels 6 × 40 = 240 km from the starting point.

Kiranmala overtakes Arun at the same point.

Kiranmala takes $\frac{240}{60}$ = 4 hrs to reach there.

Arun takes $\frac{240}{30}$ = 8 hrs to reach there.

 Kiranmala starts 8 – 4 = 4 hrs after Arun.

Hence, option (3)4 is the Answer.

selected by
11.1k points

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true