CAT 2006 | Question: 66

Question

Let $f(x) = \max (2x +1, 3 – 4x)$ where $x$ is any real number. Then the minimum possible value of $f(x)$ is:

• A. $1/3$
• B. $1/2$
• C. $2/3$
• D. $4/3$
• E. $5/3$

Answer 1

Min of f(x) = min ( max ( 2x +1, 3 -4x) ) = 5/3., at x =1/3.

Ans - 5.