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Let $f(x) = \max (2x +1, 3 – 4x)$ where $x$ is any real number. Then the minimum possible value of $f(x)$ is:

1. $1/3$
2. $1/2$
3. $2/3$
4. $4/3$
5. $5/3$

Min of f(x) = min ( max ( 2x +1, 3 -4x) ) = 5/3., at x =1/3.

Ans - 5.

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