in Quantitative Aptitude edited by
150 views
0 votes
0 votes

Consider the set $\text{S} = \{1, 2, 3, \dots, 1000\}.$ How many arithmetic progressions can be formed from the elements of $\text{S}$ that start with $1$ and with $1000$ and have at least $3$ elements?

  1. $3$
  2. $4$
  3. $6$
  4. $7$
  5. $8$
in Quantitative Aptitude edited by
13.4k points
150 views

Please log in or register to answer this question.

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true