in Quantitative Aptitude edited by
408 views
0 votes
0 votes

A group of $630$ children is arranged in rows for a group photograph session. Each row contains three fewer children than the row in front of it. What numbers of rows is not possible?

  1. $3$
  2. $4$
  3. $5$
  4. $6$
  5. $7$
in Quantitative Aptitude edited by
13.4k points
408 views

1 Answer

1 vote
1 vote

Let the no. of students in front row be x.

So, the no. of students in next rows be x–3,x−6,x–9 ... so on

If n is the no. of rows then no. of students (n=3)

x+(x–3)+(x–6)=630

x=213

 

Similarly for n=4

x+(x–3)+(x–6)+(x−9)=630

4x–18=630

 

If n=5

(4x–18)+(x−12)=630

5x–30=630

x=120

Again possible.

 

If n=6

(5x−30)+(x−15)=630

6x−45=630

6x=675

Hence n ≠ 6

 

Hence,Option (4)6 is the correct choice.

11.1k points

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true